Vereinfache so weit wie möglich.
a+bb−a−ba\dfrac{a+b}b-\dfrac{a-b}aba+b−aa−b
cc2−8c+16−2c2−6c+8\dfrac c{c^2-8c+16}-\dfrac2{c^2-6c+8}c2−8c+16c−c2−6c+82
b−ca2+ac−a−bac+c2+a2+c2a2c+ac2\dfrac{b-c}{a^2+ac}-\dfrac{a-b}{ac+c^2}+\dfrac{a^2+c^2}{a^2c+ac^2}a2+acb−c−ac+c2a−b+a2c+ac2a2+c2
10u2−11u−625u2−4\dfrac{10u^2-11u-6}{25u^2-4}25u2−410u2−11u−6
c2+c−20−c2+c+30\dfrac{c^2+c-20}{-c^2+c+30}−c2+c+30c2+c−20
7r2s12(r−s) ⋅ (2sr−2r)221rs2\dfrac{7r^2s}{12\left(r-s\right)}\;\cdot\;\dfrac{(2\mathrm{sr}-2r)^2}{21\mathrm{rs}^2}12(r−s)7r2s⋅21rs2(2sr−2r)2
(66a2)3:(4xy2)21(2a2b)3⋅(3x2y3)3 : 2a3b5\dfrac{\left(\frac66a^2\right)^3:\left(\frac{4x}{y^2}\right)^2}{\frac1{\left(2a^2b\right)^3\cdot\left(3x^2y^3\right)^3}}\;:\;\dfrac{2a^3b}5(2a2b)3⋅(3x2y3)31(66a2)3:(y24x)2:52a3b
23b2+(3b2)2−56b2(43a2b)3 : (2a3)25a3b2\dfrac{\frac23b^2+\left(\frac{3b}2\right)^2-\frac56b^2}{\left(\frac43a^2b\right)^3}\;:\;\dfrac{\left(\frac{2a}3\right)^2}{\frac{5a^3}{b^2}}(34a2b)332b2+(23b)2−65b2:b25a3(32a)2
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