Rechen- und Verständnisaufgaben zur Quadratwurzel

$x_{1/2}=\frac{-14\pm\sqrt{14^2-4\cdot8}}2$

$x_{1/2}=\frac{-5\pm\sqrt{5^2+4\cdot\sqrt{7}\cdot2\sqrt{7}}}{2\sqrt{7}}$

$\sqrt{500}+3\sqrt{98}-5\sqrt8-3\sqrt{45}$

$\sqrt{64k^2}$

$\left(\sqrt{\frac{x^5y}{5a}}:\sqrt{\frac{x^3y^3}{a^2}}\right)\cdot\sqrt{\frac{25x}a}\;\;\;\;\;\;\;\;\left(x,\;y,\;z\;>\;0\right)$

$\left(1-\sqrt3\right)\cdot\left(1+\sqrt3\right)$

$\left(\sqrt2-3\sqrt2\right)^2$

$\sqrt3\cdot\left(\frac16\sqrt{12}-3\sqrt{\frac1{27}}\right)$

$\left(2\sqrt{108}-7\sqrt{54}\right):\sqrt{27}$

$\left(\sqrt2-\sqrt{18}\right)^2$

$\left(2\sqrt7-3\right)\left(1-\sqrt{28}\right)$

$3\sqrt{63}+6\sqrt{72}-4\sqrt{28}-17\sqrt8$

$\frac1{\sqrt2}$

$\frac5{2\sqrt3}$

$\frac{25}{\sqrt{125}}$

$\frac{\sqrt x-\sqrt y}{\sqrt{x y}}$

$\frac1{\sqrt2}$

$\frac{\sqrt2-\sqrt{125}}{\sqrt5}$

$\sqrt{\mathrm x-36}$

$\sqrt{36+\mathrm x^2}$

$\frac1{\sqrt{\mathrm x+36}}$

$\sqrt{\mathrm x^2-36}$

$\sqrt{49a^4b^2}$

$\sqrt{\left(-b\right)^2}$

$\sqrt{-b}^{\;2}$

$\sqrt{\left(1-2x\right)^2}$

$\sqrt{\left(x-y\right)^2}$

$\sqrt{x^2+y^2}$

$\sqrt{x^2\cdot y^2}$

$\sqrt{x^2}=-x$

$\sqrt{\left(x-1\right)^2}=x-1$

$5\cdot\sqrt{2x}\cdot\sqrt{18x}$

$\displaystyle\frac{\sqrt{2a^2}\cdot\sqrt{12a}}{\sqrt{8a}}$

$\left(\sqrt{d-2}\right)^2$

$\sqrt{\left(d-2\right)^2}$