Bestimme die Definitionsmenge und die Lösungsmenge von:
x+1+4x+4(x+1)2−x3+x2x(x+1)=x2+4x(x+4)(x+1)+5x+15(x+1)(x+3)x+1+\frac{\displaystyle 4x+4}{\displaystyle (x+1)^2}-\frac{\displaystyle x^3+x^2}{\displaystyle x(x+1)}=\frac{\displaystyle x^2+4x}{\displaystyle (x+4)(x+1)}+\frac{\displaystyle 5x+15}{\displaystyle (x+1)(x+3)}x+1+(x+1)24x+4−x(x+1)x3+x2=(x+4)(x+1)x2+4x+(x+1)(x+3)5x+15