Gegeben: $\mathrm{\Delta }s=100\text{ m}\backslash Delta\; s=100\; \backslash text\{\; m\}$ und $\mathrm{\Delta }t=50\text{ s}\backslash Delta\; t=50\; \backslash text\{\; s\}$

Gesucht: $vv$

Lösung: $v={\displaystyle \frac{\mathrm{\Delta }s}{\mathrm{\Delta }t}}={\displaystyle \frac{100\text{ m}}{50\text{ s}}}={\displaystyle \frac{100}{50}}{\displaystyle \frac{\text{m}}{\text{s}}}=2{\displaystyle \frac{\text{m}}{\text{s}}}v=\backslash dfrac\{\backslash Delta\; s\}\{\backslash Delta\; t\}=\backslash dfrac\{100\; \backslash text\{\; m\}\}\{50\; \backslash text\{\; s\}\}=\backslash dfrac\{100\}\{50\}\backslash dfrac\{\backslash text\{m\}\}\{\backslash text\{s\}\}=2\backslash dfrac\{\backslash text\{m\}\}\{\backslash text\{s\}\}$