$\cos \left(\gamma \right)=-\sin \left(\gamma \right)$

Der/Die Winkel müssen im zweiten und vierten Quadranten liegen.

$\sin \left(\gamma \right)=\cos \left(\gamma \right)$  wenn gilt  $\gamma ={45}^{\circ }$

Dem Winkel  $\gamma ={45}^{\circ }$  entsprechen

1.Winkel

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$\gamma ={135}^{\circ }$

$-\left(\frac{\sqrt{2}}{2}\right)=-\frac{\sqrt{2}}{2}$

2.Winkel

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$Syntaxerrorfromline1column253toline1column258.Unexpecte{d}^{\prime \prime }.$

$\gamma ={315}^{\circ }$

$-(-\frac{\sqrt{2}}{2})=\frac{\sqrt{2}}{2}$

$\frac{\sqrt{2}}{2}=\frac{\sqrt{2}}{2}$