$\mathrm{\Omega }=\left\{(K;1)(K;2)(K;3)(K;4)(K;5)(K;6)(Z;1)(Z;2)(Z;3)(Z;4)(Z;5)(Z;6)\right\}\backslash Omega=\backslash left\backslash \{\backslash left(K;1\backslash right)\backslash left(K;2\backslash right)\backslash left(K;3\backslash right)\backslash left(K;4\backslash right)\backslash left(K;5\backslash right)\backslash left(K;6\backslash right)\backslash left(Z;1\backslash right)\backslash left(Z;2\backslash right)\backslash left(Z;3\backslash right)\backslash left(Z;4\backslash right)\backslash left(Z;5\backslash right)\backslash left(Z;6\backslash right)\backslash right\backslash \}$

$\Rightarrow 2\cdot 6=\backslash Rightarrow\backslash ;2\backslash cdot\; 6=$ $1212$ Elemente, da es für einen Münzwurf 2 und bei einem Würfel 6 mögliche Ergebnisse gibt.