$\begin{array}{c}14\cdot 75=\end{array}\backslash def\backslash arraystretch\{1.25\}\; \backslash begin\{array\}\{l\}14\backslash cdot75=\backslash end\{array\}$

$10\cdot 75+4\cdot 75=10\backslash cdot75+4\backslash cdot75=$

$14\cdot 70+14\cdot 5=14\backslash cdot70+14\backslash cdot5=$

$10501050$

Der Rechenweg $10\cdot 75+4\cdot 7510\backslash cdot75+4\backslash cdot75$ und $14\cdot 70+14\cdot 514\backslash cdot70+14\backslash cdot5$ ist korrekt.