Löse die Determinante nach der $2x22x2$ Formel.

$ad-bc\backslash \; ad-bc\backslash$ setze die entsprechenden Werte in die Formel ein.

$2\cdot 8-(-3)\cdot 5=16-(-15)=16+15=31\backslash \; \backslash \; 2\backslash cdot8-(-3)\backslash cdot5\backslash \; =\backslash \; 16\backslash \; -\backslash \; (-15)\backslash \; =\backslash \; 16\backslash \; +\backslash \; 15\backslash \; =\backslash \; 31$

Damit hast du