$\underline{\text{1.\ Strahlensatz}}$$\quad\Rightarrow\quad\dfrac{\overline{ZA}}{\overline{ZC}}=\dfrac{\overline{ZD}}{\overline{ZF}}$

$\rule{12cm}{0.5mm}$

$\underline{\text{2.\ Strahlensatz}}$$\quad\Rightarrow\quad\dfrac{\overline{ZD}}{\overline{DA}}=\dfrac{\overline{ZE}}{\overline{EB}}$

Berechne die Länge der Strecke $\overline{FC}$.

Es gilt:$\quad\dfrac{\overline{ZC}}{\overline{FC}}\ =\ \dfrac{{\overline{ZC}-\overline{BC}}}{\overline{EB}}\quad\Rightarrow\quad \overline{FC}\ =\ \dfrac{\overline{ZC}\cdot\overline{EB}}{\overline{ZC}-\overline{BC}}\quad\Rightarrow\quad\overline{FC}\ =\ \dfrac{168\ cm^2}{14\ cm}$

$\ \hspace{13mm}\underline{\underline{\overline{FC}\ =\ 12\ cm}}$