$1{\text{m}}^3=1000{\text{dm}}^3=1000\text{ l}\backslash \; 1\backslash \; \backslash text\{m\}^3\backslash \; =\backslash \; 1000\backslash \; \backslash text\{dm\}^3\backslash \; =\backslash \; 1000\backslash \; \backslash text\{l\}$

Volumen Schwimmbecken$=48{\text{m}}^3\cdot 1000{\displaystyle \frac{\text{l}}{{\text{m}}^3}}=48000\text{ l}\backslash \; =\backslash \; 48\backslash \; \backslash text\{m\}^3\backslash cdot1000\backslash \; \backslash dfrac\{\backslash text\{l\}\}\{\backslash text\{m\}^3\}\backslash \; =\backslash \; 48000\backslash \; \backslash text\{l\}$

Anzahl Wassertropfen im Schwimmbecken:

${\displaystyle \frac{\mathrm{4,8}\cdot {10}^4}{{\displaystyle \frac{5}{{10}^5}}}}={\displaystyle \frac{\mathrm{4,8}\cdot {10}^4\cdot {10}^5}{5}}=\mathrm{9,6}\cdot {10}^8\backslash \; \backslash dfrac\{4\{,\}8\backslash cdot10^4\}\{\backslash dfrac\{5\}\{10^5\}\}\backslash \; =\backslash \; \backslash dfrac\{4\{,\}8\backslash cdot10^4\backslash cdot10^5\}\{5\}=9\{,\}6\backslash cdot10^8$

In das Schwimmbecken passen $\mathrm{960.000.000}960.000.000$ Wassertropfen.

$1\text{ h}=3600\text{ s}\backslash \; 1\backslash \; \backslash text\{h\}=3600\backslash \; \backslash text\{s\}$

$1\text{ l}=1000\text{ ml }\backslash \; 1\backslash \; \backslash text\{l\}=1000\backslash \; \backslash text\{ml\}\backslash$oder in Potenzschreibweise${10}^3\text{ ml}\backslash \; 10^3\backslash \; \backslash text\{ml\}$

$\text{ Volumen 1 Wassertropfen}=5\cdot {10}^{-2}\text{ ml}\backslash \; \backslash text\{Volumen\backslash \; 1\backslash \; Wassertropfen\}=\backslash \; \backslash \; \backslash \; \backslash \; \backslash \; 5\backslash cdot10^\{-2\}\backslash \; \backslash text\{ml\}$

$\text{ Volumen 5 Wassertropfen}=5\cdot 5\cdot {10}^{-2}\text{ ml}\backslash \; \backslash text\{Volumen\backslash \; 5\backslash \; Wassertropfen\}=\backslash \; 5\backslash cdot5\backslash cdot10^\{-2\}\backslash \; \backslash text\{ml\}$

Volumen des verdunsteten Wassers pro Stunde:

$5\cdot 5\cdot {10}^{-2}\cdot 3600=25\cdot \mathrm{3,6}\cdot {10}^3\cdot {10}^{-2}\left[{\displaystyle \frac{\text{ml}}{\text{h}}}\right]\backslash \; 5\backslash cdot5\backslash cdot\; 10^\{-2\}\backslash cdot3600\backslash \; \backslash \; =25\backslash cdot3\{,\}6\backslash cdot10^\{3\}\backslash cdot10^\{-2\}\backslash \; \backslash left[\backslash dfrac\{\backslash text\{ml\}\}\{\backslash text\{h\}\}\backslash right]$

$=90\cdot 10=900\frac{\text{ml}}{\text{h}}\backslash \; =90\backslash cdot10=900\backslash \; \backslash frac\{\backslash text\{ml\}\}\{\backslash text\{h\}\}$

Martin hat recht, es verdunsten$900\text{ ml }\backslash \; 900\backslash \; \backslash text\{ml\}\backslash$Wasser pro Stunde.