$P\left(MJMJM\right)=\frac{3}{5}\cdot \frac{2}{4}\cdot \frac{2}{3}\cdot \frac{1}{2}\cdot \frac{1}{1}P\backslash left(MJMJM\backslash right)=\backslash frac\{3\}\{5\}\backslash cdot\backslash frac\{2\}\{4\}\backslash cdot\backslash frac\{2\}\{3\}\backslash cdot\backslash frac\{1\}\{2\}\backslash cdot\backslash frac\{1\}\{1\}$

$=\mathrm{0,1}=10\mathrm{\%}=0\{,\}1=10\backslash ,\backslash \%$

$P(MMMJJ)=\frac{3}{5}\cdot \frac{2}{4}\cdot \frac{1}{3}\cdot \frac{2}{2}\cdot \frac{1}{1}=\mathrm{0,1}=10\mathrm{\%}P(MMMJJ)=\backslash frac35\backslash cdot\backslash frac24\backslash cdot\backslash frac13\backslash cdot\backslash frac22\backslash cdot\backslash frac11=0\{,\}1=10\backslash ,\backslash \%$

$P(JJMMM)=\frac{2}{5}\cdot \frac{1}{4}\cdot \frac{3}{3}\cdot \frac{2}{2}\cdot \frac{1}{1}=\mathrm{0,1}=10\mathrm{\%}P(JJMMM)\; =\; \backslash frac25\backslash cdot\backslash frac14\backslash cdot\backslash frac33\backslash cdot\backslash frac22\backslash cdot\backslash frac11=0\{,\}1=10\backslash ,\backslash \%$

$P(JMMMJ)=\frac{2}{5}\cdot \frac{3}{4}\cdot \frac{2}{3}\cdot \frac{1}{2}\cdot \frac{1}{1}=\mathrm{0,1}=10\mathrm{\%}P(JMMMJ)=\backslash frac25\backslash cdot\backslash frac34\backslash cdot\backslash frac23\backslash cdot\backslash frac12\backslash cdot\backslash frac11=0\{,\}1=10\backslash ,\backslash \%$

$\Rightarrow P(\text{3 M}\ddot{\text{a}}\text{dchen hintereinander})=10\mathrm{\%}+10\mathrm{\%}+10\mathrm{\%}=30\mathrm{\%}\backslash Rightarrow\; P(\backslash text\{3\; Mädchen\; hintereinander\})=\; 10\backslash ,\backslash \%+10\backslash ,\backslash \%+10\backslash ,\backslash \%=30\backslash ,\backslash \%$