Es ist

$\begin{array}{c}B=\{\mathrm{1,3},5\}\Rightarrow \mid B\mid =3\\ \mathrm{\Omega }=\{\mathrm{1,2},\mathrm{3,4},\mathrm{5,6}\}\Rightarrow \mid \mathrm{\Omega }\mid =6\end{array}\backslash def\backslash arraystretch\{1.25\}\; \backslash begin\{array\}\{l\}B=\backslash \{1\{,\}3,5\backslash \}\backslash ;\backslash ;\backslash ;\backslash ;\backslash ;\backslash ;\backslash ;\backslash ;\backslash ;\backslash ;\backslash ;\backslash ;\backslash ,\backslash Rightarrow\backslash ;\backslash ;\backslash left|B\backslash right|=3\backslash \backslash \backslash Omega=\backslash \{1\{,\}2,3\{,\}4,5\{,\}6\backslash \}\backslash ;\backslash ;\backslash Rightarrow\backslash ;\backslash ;\backslash left|\backslash Omega\backslash right|=6\backslash end\{array\}$

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