$[(1000-10):10-10]\cdot 10+10=\backslash lbrack(1000-10):10-10\backslash rbrack\backslash cdot10+10=$

Berechne die runde Klammer und dann die eckige Klammer.

Beachte Punkt geht vor Strich.

$[990:10-10]\cdot 10+10=\backslash lbrack990:10-10]\backslash cdot10+10=$

$[99-10]\cdot 10+10=\backslash lbrack99-10\backslash rbrack\backslash cdot10+10=$

$89\cdot 10+10=89\backslash cdot10+10=$

$890+10=900890+10=900$

Für diese Aufgabe musst du die Schriftliche Division beherrschen.

$\begin{array}{c}9096:758=12\\ \underset{‾}{-758}\\ 1516\\ \underset{‾}{-1516}\\ 0\end{array}\backslash def\backslash arraystretch\{1.25\}\; \backslash begin\{array\}\{l\}\; \backslash ,\backslash ,\; \backslash ,\backslash ,\; 9096\; :\; 758\; =\; 12\; \backslash \backslash \; \backslash underline\{-758\}\backslash \backslash \; \backslash ,\backslash ,\backslash ,\backslash ,\backslash ,151\backslash color\{\#ff6600\}\{6\}\; \backslash \backslash \; \backslash ,\backslash ,\backslash underline\{-1516\}\; \backslash \backslash \; \backslash ,\backslash ,\backslash ,\backslash ,\backslash ,\backslash ,\backslash ,\backslash ,\; \backslash ,\backslash ,\backslash ,\backslash ,\backslash ,\backslash ,\backslash ,0\; \backslash end\{array\}$

Das Ergebnis der Aufgabe lautet 12.