Der Weg $(s)(s)$ und die Geschwindigkeit $(v)(v)$ sind bekannt:

$s=6km;s\backslash \; =\backslash \; 6\backslash \; km;\backslash qquad$ $v=12{\displaystyle \frac{km}{h}}v\backslash \; =\backslash \; 12\backslash dfrac\{km\}\{h\}$

Die Formel zur Berechnung der Geschwindigkeit lautet:

$v={\displaystyle \frac{s}{t}}\Rightarrow t={\displaystyle \frac{s}{v}}v\backslash \; =\backslash \; \backslash dfrac\{s\}\{t\}\backslash \; \backslash Rightarrow\backslash \; t\backslash \; =\backslash \; \backslash dfrac\{s\}\{v\}$

$t={\displaystyle \frac{6km}{12{\displaystyle \frac{km}{h}}}}\Rightarrow t={\displaystyle \frac{6km\cdot h}{12km}}t\backslash \; =\backslash \; \backslash dfrac\{6\backslash \; km\}\{\{12\}\backslash dfrac\{km\}\{h\}\}\backslash \; \backslash Rightarrow\backslash \; t\backslash \; =\backslash \; \backslash dfrac\{6\backslash \; km\backslash cdot\{h\}\}\{12\backslash \; km\}$

$t=\mathrm{0,5}ht\backslash \; =\backslash \; 0\{,\}5\backslash \; h$

Der Dampfer benötigt $\mathrm{0,5}0\{,\}5$ Stunden von Brücke $AA$ zu Brücke $BB$.