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\displaystyle (3x-2y)^2-6xy

=

\displaystyle \left(\left(3x\right)^2-2\cdot3x\cdot\left(-2y\right)+\left(2y\right)^2\right)-6xy

=

\displaystyle \left(9x^2-12xy+4y^2\right)-6xy

=

\displaystyle 9x^2-18xy+4y^2

$\displaystyle (3x-2y)^2-6xy$	$=$	$\displaystyle \left(\left(3x\right)^2-2\cdot3x\cdot\left(-2y\right)+\left(2y\right)^2\right)-6xy$
	$=$	$\displaystyle \left(9x^2-12xy+4y^2\right)-6xy$
	↓	Fasse zusammen
	$=$	$\displaystyle 9x^2-18xy+4y^2$