2021 - lernen mit Serlo!

\displaystyle (2-x)\cdot x

=

\displaystyle -(x^2-5)

\displaystyle 2x-x^2

=

\displaystyle -x^2+5

\displaystyle +x^2

\displaystyle 2x

=

\displaystyle 5

\displaystyle :2

\displaystyle x

=

\displaystyle 2{,}5

$\displaystyle (2-x)\cdot x$	$=$	$\displaystyle -(x^2-5)$
	↓	Klammern auflösen
$\displaystyle 2x-x^2$	$=$	$\displaystyle -x^2+5$	$\displaystyle +x^2$
$\displaystyle 2x$	$=$	$\displaystyle 5$	$\displaystyle :2$
$\displaystyle x$	$=$	$\displaystyle 2{,}5$