Flächeninhalt eines Dreiecks

$F_{Dreieck}={\displaystyle \frac{1}{2}}\cdot g\cdot hF\_\{Dreieck\}=\backslash dfrac\{1\}\{2\}\backslash cdot\; g\backslash cdot\; h$

$g=5,6cmg=5\{,\}6cm$

$h=(12cm-5,6cm):2h=(12cm-5\{,\}6cm):2$

$h=3,2cmh=3\{,\}2cm$

$F_{Dreieck}={\displaystyle \frac{1}{2}}\cdot 5,6cm\cdot 3,2cmF\_\{Dreieck\}=\backslash dfrac\{1\}\{2\}\backslash cdot\; 5\{,\}6cm\backslash cdot\; 3\{,\}2cm$

$F_{Dreieck}=8,96c{m}^{2}F\_\{Dreieck\}=8\{,\}96cm^2$

Flächeninhalt eines Quadrats

$F_{Quadrat}=a^{2}F\_\{Quadrat\}=a^2$

$a=5,6cm:4a=5\{,\}6cm:4$

$a=1,4cma=1\{,\}4cm$

$F_{Quadrat}=1,4cm\cdot 1,4cmF\_\{Quadrat\}=1\{,\}4cm\backslash cdot\; 1\{,\}4cm$

$F_{Quadrat}=1,96c{m}^{2}F\_\{Quadrat\}=1\{,\}96cm^2$

Die grau markierten Fläche besteht aus aus 2 Dreiecken und 8 Quadraten.

$F_{grau}=2\cdot 8,96c{m}^2+8\cdot 1,96c{m}^{2}F\_\{grau\}=\; 2\backslash cdot\; 8\{,\}96cm^2+8\backslash cdot\; 1\{,\}96cm^2$

$F_{grau}=17,92c{m}^2+15,68c{m}^{2}F\_\{grau\}=\; 17\{,\}92cm^2+15\{,\}68cm^2$

$F_{grau}=33,60c{m}^{2}F\_\{grau\}=\; 33\{,\}60cm^2$