$A_{\text{Raute}}=\frac{1}{2}\cdot e\cdot fA\_\{\backslash text\{Raute\}\}=\backslash frac12\backslash cdot\; e\backslash cdot\; f$

$A_{\text{Raute}}={\displaystyle \frac{1}{2}}\cdot 8\text{ cm}\cdot 6\text{ cm}=24{\text{ cm}}^{2}A\_\{\backslash text\{Raute\}\}=\backslash dfrac\{1\}\{2\}\backslash cdot\; 8\backslash text\{\; cm\}\backslash cdot\; 6\backslash text\{\; cm\}=24\backslash text\{\; cm\}^2$

Der Flächeninhalt der Raute beträgt $24{\text{cm}}^{2}24~\backslash text\{cm\}^2$.