Aufgaben zu linearen Ungleichungen

$2x-3\geq4$

$3-0{,}2x\leq4$

$\frac13x-5\leq\frac14x+3$

$\frac{2-x}3+5\geq\frac x2$

$-\frac12\cdot\left(x-6\right)<6$

$3\left(x-3\right)\geq5\left(1-\frac x2\right)$

$\frac12\left(x-5\right)>0$

$2x+\frac52<-(3+4x)-3$

$\frac x5+3\geq\frac x2$

$-3<2(x-2)<5$

$\frac12-3x>x+2{,}75$

$\frac58\cdot\left(x-0{,}4\right)-2<x-10$

$\frac37\cdot\left(2-3x\right)-1\geq\frac12\cdot\left(3x-5\right)$

$\frac{12-5x}7\leq3$

$\frac{8-3x}5\geq5-2x$

$\frac{x-0{,}3}5\leq\frac{7-x}2$

$\frac35\cdot\frac{2-x}4>\frac{0{,}4\cdot\left(x-1\right)}{15}$