$kgV(\mathrm{2,3},\mathrm{4,9})=36kgV(2\{,\}3,4\{,\}9)=36$

${\displaystyle \frac{1}{2}}={\displaystyle \frac{18}{36}}\backslash dfrac\{1\}\{2\}=\; \backslash dfrac\{18\}\{36\}$

${\displaystyle \frac{2}{3}}={\displaystyle \frac{24}{36}}\backslash dfrac\{2\}\{3\}=\; \backslash dfrac\{24\}\{36\}$

${\displaystyle \frac{3}{4}}={\displaystyle \frac{27}{36}}\backslash dfrac\{3\}\{4\}=\; \backslash dfrac\{27\}\{36\}$

${\displaystyle \frac{3}{2}}={\displaystyle \frac{54}{36}}\backslash dfrac\{3\}\{2\}=\; \backslash dfrac\{54\}\{36\}$

${\displaystyle \frac{2}{9}}={\displaystyle \frac{8}{36}}\backslash dfrac\{2\}\{9\}=\; \backslash dfrac\{8\}\{36\}$

=> ${\displaystyle \frac{1}{2}}\backslash dfrac\{1\}\{2\}$ und ${\displaystyle \frac{2}{9}}\backslash dfrac\{2\}\{9\}$ sind die beiden kleinsten Zahlen und ergeben die Summe

${\displaystyle \frac{18+8}{36}}={\displaystyle \frac{26}{36}}={\displaystyle \frac{13}{18}}\backslash dfrac\{18+8\}\{36\}=\; \backslash dfrac\{26\}\{36\}=\; \backslash dfrac\{13\}\{18\}$