L(t) | = | 1+2,2075⋅e−170⋅k⋅t170 | |
| ↓ | Setze L(3,64)=100 ein. |
100 | = | 1+2,2075⋅e−170⋅k⋅3,64170 | |
100 | = | 1+2,2075⋅e−618,8⋅k170 | ⋅(1+2,2075⋅e−618,8⋅k) |
100⋅(1+2,2075⋅e−618,8⋅k) | = | 170 | :100 |
1+2,2075⋅e−618,8⋅k | = | 1,7 | −1 |
2,2075⋅e−618,8⋅k | = | 0,7 | :2,2075 |
e−618,8⋅k | = | 2,20750,7 | ln |
−618,8⋅k | = | ln(2,20750,7) | :(−618,8) |
k | = | (−618,8)ln(2,20750,7) | |
k | ≈ | 0,001856 | |