$2^{10}:2^7=2^{10-7}=2^3=82^\{10\}:2^\{7\}=2^\{10-7\}=2^3=8$

$3+({\displaystyle \frac{1}{2}}{)}^{-1}=3+{\displaystyle \frac{1}{({\displaystyle \frac{1}{2}}{)}^1}}=3+2=53+(\backslash dfrac\{1\}\{2\})^\{-1\}=\; 3+\backslash dfrac\{1\}\{(\backslash dfrac\{1\}\{2\})^1\}=3+2=5$