Leitkante $=a+\mathrm{112,5}=a+112\{,\}5$

Berechne a mit Hilfe des Satzes von Pythagoras.

$a^2={22}^2+{21}^2=484+441=925a^2=22^2+21^2=484+441=925$

$a=\sqrt{925}=\mathrm{30,41}a=\backslash sqrt\{925\}=30\{,\}41$

Leitkante$=\mathrm{30,41}+\mathrm{112,5}=\mathrm{142,91}\backslash \; =30\{,\}41+112\{,\}5=142\{,\}91$

Die Leitkante ist $\mathrm{142,91}\text{ cm}142\{,\}91\backslash cm$ lang.

$\sin (\alpha )={\displaystyle \frac{\text{Gegenkathete}}{\text{Hypotenuse}}}\backslash sin(\backslash alpha)=\backslash displaystyle\backslash frac\{\backslash text\{Gegenkathete\}\}\{\backslash text\{Hypotenuse\}\}$

$\sin (\alpha )={\displaystyle \frac{21}{\mathrm{30,41}}=\mathrm{0,69}}\backslash sin(\backslash alpha)=\backslash displaystyle\backslash frac\{21\}\{30\{,\}41\}=0\{,\}69$

$\alpha \approx \mathrm{43,67}\mathrm{°}\alpha \backslash approx43\{,\}67°$