${\displaystyle \frac{3}{5}}<{\displaystyle \frac{4}{5}}<{\displaystyle \frac{7}{5}}\backslash dfrac35\backslash lt\backslash dfrac45\backslash lt\backslash dfrac75$

${\displaystyle \frac{7}{5}}\backslash dfrac75$ $<\backslash lt$ ${\displaystyle \frac{7}{3}}\backslash dfrac73$

Der Bruch ${\displaystyle \frac{9}{2}}\backslash dfrac92$ ergibt erweitert : ${\displaystyle \frac{27}{6}}\backslash dfrac\{27\}6$ Also gilt: ${\displaystyle \frac{7}{6}}\backslash dfrac76$ $<\backslash lt$ ${\displaystyle \frac{27}{6}}\backslash dfrac\{27\}6$

${\displaystyle \frac{23}{9}}\backslash dfrac\{23\}9$ $<\backslash lt$ ${\displaystyle \frac{23}{8}}\backslash dfrac\{23\}8$ $<\backslash lt$ ${\displaystyle \frac{23}{5}}\backslash dfrac\{23\}5$

Der Bruch ${\displaystyle \frac{2}{3}}\backslash dfrac23$ ergibt erweitert: ${\displaystyle \frac{8}{12}}\backslash dfrac8\{12\}$

Also gilt: ${\displaystyle \frac{5}{12}}\backslash dfrac5\{12\}$ $<\backslash lt$ ${\displaystyle \frac{8}{12}}\backslash dfrac8\{12\}$