Gib für folgende Funktionen die maximale Definitionsmenge an (G=R)\left(G=ℝ\right)(G=R) .
f(x)=4x−32x−5f(x)=\dfrac{4x-3}{2x-5}f(x)=2x−54x−3
f(x)=3x3+7x2−2xf(x)=\dfrac{3x^3+7}{x^2-2x}f(x)=x2−2x3x3+7
f(x)=2x+x719x2+13x+14f\left(x\right)=\dfrac{2x+x^7}{\frac19x^2+\frac13x+\frac14}f(x)=91x2+31x+412x+x7
f(x)=2x4−x20,01x2−1f\left(x\right)=\dfrac{2x^4-x^2}{0{,}01x^2-1}f(x)=0,01x2−12x4−x2
f(x)=7x+4f\left(x\right)=\sqrt{7x+4}f(x)=7x+4
f(x)=x2−5x+6f\left(x\right)=\sqrt{x^2-5x+6}f(x)=x2−5x+6
f(x)=17x+5x−3f(x)=\sqrt{17x}+5x-3f(x)=17x+5x−3
f(x)=x2−4x+36f(x)=\sqrt[6]{x^2-4x+3}f(x)=6x2−4x+3
f(x)=ln(x−5)f(x)=\ln(x-5)f(x)=ln(x−5)
f(x)=ln(6x−x2−9)f\left(x\right)=\ln\left(6x-x^2-9\right)f(x)=ln(6x−x2−9)
f(x)=log6(x3−7x)f(x)=\mathrm{log}_6(x^3-7x)f(x)=log6(x3−7x)
f(x)=5x tan(x)f\left(x\right)=5x\;\tan\left(x\right)f(x)=5xtan(x)
f(x)=7x2tan(2−x)f\left(x\right)=7x^2\tan\left(2-x\right)f(x)=7x2tan(2−x)
f(x)=(x+5) tan (x2−12π)f\left(x\right)=\left(x+5\right)\;\tan\;\left(x^2-\frac12\pi\right)f(x)=(x+5)tan(x2−21π)
f(x)=1x2+6x+9f\left(x\right)=\dfrac1{\sqrt{x^2+6x+9}}f(x)=x2+6x+91
f(x)=lg(x2−x)x+2f\left(x\right)=\dfrac{\lg\left(x^2-x\right)}{\sqrt{x+2}}f(x)=x+2lg(x2−x)
f(x)=1+3x+33x2sin(x)f\left(x\right)=\dfrac{1+3x+33x^2}{\sin\left(x\right)}f(x)=sin(x)1+3x+33x2
f(x)=123451−sin(x−12π)f\left(x\right)=\dfrac{12345}{1-\sin\left(x-\frac12\pi\right)}f(x)=1−sin(x−21π)12345
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