Berechne $x^2-x=x^2-x=$ für

$x=1=>x=1\; =>$ $1^2-1=1-1=01^2-1=1-1=0$

$x=\mathrm{0,5}=>x=0\{,\}5=>$ ${\mathrm{0,5}}^2-\mathrm{0,5}=\mathrm{0,25}-\mathrm{0,5}=-\mathrm{0,25}<00\{,\}5^2-0\{,\}5=0\{,\}25-0\{,\}5=-0\{,\}25\backslash lt0$

$x=3=>x=3=>$ $3^2-3=9-3=6\mathrm{\ne }33^2-3=9-3=6\backslash neq3$

$x=\mathrm{1,1}=>x=1\{,\}1=>$ ${\mathrm{1,1}}^2-\mathrm{1,1}=\mathrm{1,21}-\mathrm{1,1}=\mathrm{0,11}>01\{,\}1^2-1\{,\}1=1\{,\}21-1\{,\}1=0\{,\}11>0$