7Subtraktion (2/2)

Man hat die Vektoren

$\vec{v}=\left(\begin{array}{c}-3\\ 7\end{array}\right)\backslash vec\; v\; =\; \backslash begin\{pmatrix\}-3\backslash \backslash 7\backslash end\{pmatrix\}$ und $\vec{w}=\left(\begin{array}{c}-6\\ 2\end{array}\right)\backslash ,\backslash vec\; w\; =\; \backslash begin\{pmatrix\}-6\backslash \backslash 2\backslash end\{pmatrix\}\backslash ,$ gegeben.

Du sollst nun die Vektorsubtraktion von $\vec{v}\backslash vec\; v$ und $\vec{w}\backslash vec\; w$ bestimmen. Bilde also die Differenz:

$\overrightarrow{u}=\overrightarrow{v}-\overrightarrow{w}=\left(\begin{array}{c}-3\\ 7\end{array}\right)-\left(\begin{array}{c}-6\\ 2\end{array}\right)=\left(\begin{array}{c}-3-(-6)\\ 7-2\end{array}\right)=\left(\begin{array}{c}3\\ 5\end{array}\right)\backslash overrightarrow\; u=\backslash overrightarrow\; v-\backslash overrightarrow\; w=\backslash begin\{pmatrix\}-3\backslash \backslash 7\backslash end\{pmatrix\}-\backslash begin\{pmatrix\}-6\backslash \backslash 2\backslash end\{pmatrix\}=\backslash begin\{pmatrix\}-3-(-6)\backslash \backslash 7-2\backslash end\{pmatrix\}=\backslash begin\{pmatrix\}3\backslash \backslash 5\backslash end\{pmatrix\}$

Wie das geometrisch aussieht, siehst du im Bild rechts.